In a single throw of two dice, find

P (a total of 9 or 11)


We know that,


Probability of occurrence of an event


Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),


(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),


(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),


(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) ,


(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) ,


(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)


Desired outcomes are (3, 6), (4, 5), (5, 4), (6, 3), (6, 5) , (5, 6)


Total no.of outcomes are 36 and desired outcomes are 6


Therefore, probability of getting total equal to 9 or 11



Conclusion: Probability of getting total equal to 9 or 11, when two dice are rolled is


1