A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).

Question

Philoid · Accepted Answer

Given : A,B,C are mutually exclusive events and exhaustive events

P(B) = (3/2) P(A) and P(C) = (1/2) P(B)

To find : P(A)

Formula used : P(A) + P(B) + P(C) = 1

For mutually exclusive events A,B,and C , P(A and B) = P(B and C) = P(A and C)= 0

Let P(A) = x , P(B) = (3/2) P(A) = x , P(C) = (1/2) P(B) = x = x

x + x + x = 1

x = 1

x =

P(A) = x =

P(A) =

A, B, C are three mutually exclusive and exhaustive events associated with a random experiment.If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).

A, B, C are three mutually exclusive and exhaustive events associated with a random experiment.
If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).