A die is thrown twice. What is the probability that at least one of the two throws comes up with the number 4?

Given : A die is thrown twice


To find : Probability that at least one of the two throws comes up with the number 4


The formula used : Probability =


A die is numbered from 1 to 6


When a die is thrown twice, total number of outcomes = 62 = 36


Favourable outcomes =


{(4,1) ,(4,2) ,(4,3) ,(4,4) ,(4,5) ,(4,6) ,(1,4) ,(2,4) ,(3,4) ,(5,4) , (6,4)}


Favourable number of outcomes = 11


Probability that at least one of the two throws comes up with the number 4 =


The probability that at least one of the two throws comes up with the number 4 =


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