If Taking log on both sideslog y = acos-1x log elog y = acos-1xDifferentiating with respect to x⇒ Differentiating with respect to x⇒ ⇒ ⇒ Hence Proved
Taking log on both sides
log y = acos-1x log e
log y = acos-1x
Differentiating with respect to x
⇒
Hence Proved