If y = xx Taking log on both sides log y = x log x Differentiating with respect to x ⇒ Differentiating with respect to x ⇒ ⇒ Hence Proved
…(i)
[putting value of (1 + log x) from (i) ]
1
If y = xx Taking log on both sides log y = x log x Differentiating with respect to x ⇒ Differentiating with respect to x ⇒ ⇒ Hence Proved …(i) [putting value of (1 + log x) from (i) ]