Evaluate the following integrals:


To find: Value of


Formula used:


We have, … (i)


Let (sinx – cosx) = t




t2 = sin2x - 2sinx. cosx + cos2x


t2 = 1 - 2sinx.cosx


2sinx.cosx = 1 - t2


sin2x = 1 - t2


Putting this value in equation (i)





Let


… (ii)



Now if


Then cosθ =


cosθ =


cosθ =


cosθ =


Now tanθ =


Now tanθ =



Comparing the value θ from eqn. (ii)



Dividing Numerator and denominator from cosx



Ans.)


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