Evaluate the following integrals:
(i)
(ii)
i)
⇒
Now, we know that 1-cos2nx=2sin2nx
So, applying this identity in the given integral, we get,
⇒
Ans:
(ii)
We know that 1-cos2x=sin2x
⇒
⇒Put cosx=t
⇒-sinxdx=dt
⇒
⇒
⇒
⇒
Resubstituting the value of t=cosx we get,
⇒
Ans: