Evaluate the following integrals:
Substitute 3x+5=u
⇒3dx=du
⇒dx=du/3
⇒
Now We know that 1-cos2x=sin2x ,
⇒Substitute sinu=t
⇒cosu du=dt
Resubstituting the value of t=sinu and u=3x+5 we get,
Ans: