Evaluate the following integrals:



Substitute 2x-3=u


2dx=du


dx=du/2



We know that 1-cos2x=sin2x



Put cosu=t


-sinxdu=dt







Resubstituting the value of t=cosu and u=2x-3 we get




Now as we know cos(-x)=cosx



=


Ans:


1