Evaluate the following integrals:
(i)
(ii)
⇒
1-cos2x=2sin2x and 1+cos2x=2cos2x
Now sec2x-1=tan2x
⇒tanx-x+c
Ans: tanx-x+c
Now cosec2x-1=cot2x
⇒-cotx-x+c
Ans: -cotx-x+c