Evaluate the following integrals:


To Find :


Now, can be written as


i.e.,


Here , let x – 2 = y dx = dy


Therefore, can be written as


Formula Used: = log |x +|+ C


Since is of the form with change in variable.


= log |y +|+ C


= log |y +|+ C


= 2 log |y +|+ C


Since , x – 2 = y and dx = dy


= 2 log |(x-2) +|+C Therefore,


= 2 log |(x - 2) +|+ C


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