Evaluate the following integrals:
To Find :
Now, can be written as
i.e,
Here , let x + 3 = y dx = dy
Therefore, can be written as
Formula Used: =
log |x +
|+ C
Since is of the form
with change in variable.
=
log |y +
|+ C
= log |y +
|+ C
Since , x + 3 = y and dx = dy
=
log |(x + 3) +
|+C
Therefore,
=
log |(x + 3) +
|+C