Evaluate the following integrals:
To Find :
Now, can be written as
i.e,
Here , let x + 3 = y dx = dy
Therefore, can be written as
Formula Used: = log |x +|+ C
Since is of the form with change in variable.
= log |y +|+ C
= log |y +|+ C
Since , x + 3 = y and dx = dy
= log |(x + 3) +|+C
Therefore,
= log |(x + 3) +|+C