Evaluate the following integrals:


To Find :


Now, can be written as


=


=


Now solving,


Let = u dx =


Thus, becomes


Now , = = ) =


=


Now solving,


Now, can be written as


Formula Used: = log |x +|+ C


Since is of the form .


= log |x +|+ C


= log |x +|+ C


Therefore,


= + log |x +|+ C


Hence ,


= + log |x +|+ C


1