Find the general solution of each of the following differential equations: e x tan y dx + (1 – e x ) sec 2 y dy = 0

Question

Philoid · Accepted Answer

Rearranging all the terms we get:

Integrating both the sides we get:

⇒log|1 - e^x| = log|tany| - logc

⇒log|1 - e^x| + logc = log|tany|

⇒tany = c(1 - e^x)

Ans: tany = c(1 - e^x)