Find the general solution of each of the following differential equations:
cos x(1 + cos y)dx – sin y(1 + sin x)dy = 0
Given: cosx(1+cosy)dx-siny(1+sinx)dy=0
Dividing the whole equation by (1+sinx)(1+cosy), we get,
⇒ 
⇒ log|1+sinx|+log|1+cosy|=logc
⇒ (1+sinx)(1+cosy)=c
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