Solve (1 + x2) sec2 y dy + 2x tan y dx = 0, given that 
when x = 1.
we have, (1 + x2) sec2 y dy + 2x tan y dx = 0,
Given that, 
when x=1
⇒ 
⇒ 
⇒ 
⇒ 
For 
We have, 
c = 2,
Hence the required particular solution is:-
1
Solve (1 + x2) sec2 y dy + 2x tan y dx = 0, given that when x = 1.
we have, (1 + x2) sec2 y dy + 2x tan y dx = 0,
Given that, when x=1
⇒
⇒
⇒
⇒
For
We have,
c = 2,
Hence the required particular solution is:-