Here, S_n=2n²+3n

So, S₁=2+3=5=t₁

And S₂=2×2²+3×2

=8+6=14

So, t₂=S₂-S₁

=14-5

=9

Now, common difference of A.P. is given by

d=t₂-t₁

=9-5

=4

So, n^th term of A.P. is

a_n=t₁+(n-1)d

=5+(n-1)4

=5+4n-4

=4n+1