Mark the correct alternative in the following:
If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is
Here,a7=34 and a13=64
i.e. a+6d=34____(i) and a+12d=64_____(ii)
Subtracting (i) from (ii) we get,
(12-6)d=64-34
∴6d=30
∴ d=5
Substituting d=5 in (i) we get,
a+6(5)=34
∴a+30=34
∴ a=4
Now,18th term is given by a18=a+17d
=4+17×5
=89