Mark the correct alternative in the following:

If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is


Here,a7=34 and a13=64


i.e. a+6d=34____(i) and a+12d=64_____(ii)


Subtracting (i) from (ii) we get,


(12-6)d=64-34


6d=30


d=5


Substituting d=5 in (i) we get,


a+6(5)=34


a+30=34


a=4


Now,18th term is given by a18=a+17d


=4+17×5


=89

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