Mark the correct alternative in the following:
If in an A.P., the pth term is q and term is zero, then the
term is
Here, ap=q and a(p+q)=0
i.e. a+(p-1)d=q______(1)
and a+(p+q-1)d=0_____(2)
Subtracting (1) from (2) we get,
qd=-q
∴ d=-1
substituting this in (2) we get,
a+(p+q-1)(-1)=0
∴ a=p+q-1
So, aq=a+(q-1)d
=p+q-1+(q-1)(-1)