In how many ways 4 women draw water from 4 taps, if no tap remains unused?
1st woman can draw water from anyone of the 4 taps.
Now, as, it is given, that, no tap should remain unused so, 2nd woman can draw water from any of the remaining 3 taps.
Similarly, 3rd women can draw water from any of the remaining 2 taps.
And, 4th woman have to draw water from the remaining 1 tap.
As, the operations are dependent, so, total number of ways
= 4!
Alternative Approach:
The number of permutations of 4 objects taken 4 at a time is = 4P4 = 4!.