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A 5-digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4 and 5 without repetition. The total number of ways in which this can be done is
5-digit number divisible by 3 can be formed using 0, 1, 2, 4, 5 and 1, 2, 3, 4, 5.
When, the 5-digit number is formed using the digits 0, 1, 2, 4 and 5
So, the number of ways in which 5-digit number divisible by 3 can be formed using 0, 1, 2, 4, 5 can be done is 4×4×3×2×1
= 96.
So, the number of ways in which 5-digit number divisible by 3 can be formed using 1, 2, 4, 5 can be done is = 5P5
= 120.
The total number of ways in which 5-digit number divisible by 3 can be formed using 0, 1, 2, 3, 4, 5 can be done is = 96 + 120
= 216.