Mark the correct alternative in the following:

If then the values of k are








⇒k2 +9k+20=22(k-1)


⇒k2 +9k-22k+20+22=0


⇒k2 -13k+42=0


⇒k2 -6k-7k+42=0


⇒k(k-6)-7(k-6)=0


⇒(k-6)(k-7)=0


∴k=6 and 7.

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