If , then write the values of n.

35Cn+7 = 35C4n-2


n + 7 + 4n – 2 = 35 ( nCx = nCy ⇒ n = x + y or x = y )


5n + 5 = 35


5n = 30


n = 6


And,


n + 7 = 4n – 2


3n = 9


n = 3


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