Mark the correct alternative in the following:
If 
, then x =
nCr + nCr+1 = n+1Cx (Given)
Now, we have ⇒
nCr + nCr-1 = n+1Cr ⇒ (1)
From (1) and (Given) we have,
n+1Cr+1 = n+1Cx
r + 1 = x ( nCx = nCy ⇒ n = x + y or x = y )
1
Mark the correct alternative in the following:
If , then x =
nCr + nCr+1 = n+1Cx (Given)
Now, we have ⇒
nCr + nCr-1 = n+1Cr ⇒ (1)
From (1) and (Given) we have,
n+1Cr+1 = n+1Cx
r + 1 = x ( nCx = nCy ⇒ n = x + y or x = y )