Mark the correct alternative in the following :

If in the expansion of (1 + y)n, the coefficients of 5th, 6th and 7th terms are in A.P., then n is equal to


Given:




T5; T6& T7


Since T5 , T6 & T7 are in AP


Then; 2(T6) = T5 + T7


i.e.






30+(n-4) (n-5)-12(n-4)=0


30+n2-9n+20-12n+48=0


n2-21n+98=0


(n-7) (n-14)=0


n=7,14

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