Mark the correct alternative in the following :

If the sum of odd numbered terms and the sum of even numbered terms in the expansion of are A and B respectively, then the value of is.


Given:




= A+B




= A-B


(x2-a2 )n= [(x+a)(x-a)]n


=(x+a)n (x-a)n


= (A+B) (A-B)


=A2-B2

1