Let A and B be two sets having 4 and 7 elements respectively. Then write the maximum number of elements that can be.
Here, n(A)=4 and n(B)=7
Now, n(A⋃B) =n(A)+n(B)-n(A⋂B)
=4+7-n(A⋂B)
=11-n(A⋂B)
So, n(A⋃B) is maximum whenever n(A⋂B) is minimum and it is possible only when A⋂B=ϕ
Now, A⋂B=ϕ then min(n(A⋂B)) =0.
∴ min(n(A⋃B))=11-0=11