Mark the correct alternative in the following:

An investigator interviewed 100 students to determine the performance of three drinks: milk, coffee and tea. The investigator reporter that 10 students take all three drinks milk, coffee and tea; 20 students take milk coffee; 25 students take milk and tea; 20 students take coffee and tea; 12 students take milk only; 5 students take coffee only and 8 students take tea only. Then the number of students who did not take any of three drinks is


Let U be the set of students which are interviewed by investigator


A be the set of students which take milk


B be the set of students which take coffee


C be the set of students which take tea


Then ,n(U)=100 ,n(A)=12, n(B)=5 ,n(C)=8


Also, (A⋂B⋂C) means students who drink all of three=10


(A⋂B) means students who drink milk and coffee =20-10=10


(B⋂C) means students who drink coffee and tea =20-10=10


(A⋂C) means students who drink milk and tea =25-10=15


A⋃B⋃C is the total of above =12+5+8+10+10+15+10=70


The number of students who didn’t take any drink =100-70=30

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