We have xφy |x| = y

By checking the options,

A. (2 + 3i) φ 13

X = 2 + 3i;

= √13

Therefore, |x|≠ y.

So, option A is incorrect.

B. 3 φ (−3)

X = 3;

= 3

3 ≠(-3)

Therefore, option B is incorrect.

C. (1 + i) φ 2

X = 1+ i;

= √2

√2 ≠ 2

Therefore, option C is also incorrect.

D. iφ 1

x = i;

= 1

1 = 1

|x| = y.

Therefore, option D is correct.