Mark the correct alternative in the following:

Let R be a relation on N defined by x + 2 y = 8. The domain of R is


We have , x + 2y = 8

y =


since, x and y are Natural numbers, So .. x must be an even number..


if x = 2, y = 3;


if x = 4, y = 2;


if x = 6, y = 1.


So, relation R = {(2, 3), (4, 2), (6, 1)}


Now, domain of R is {2, 4, 6}.


So, option C is correct.

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