Mark the correct alternative in the following: R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x − 3. Then, R − 1 is

Question

Philoid · Accepted Answer

Since, y = x – 3;

Therefore, for x = 11, y = 8.

For x = 12, y = 9.[ But the value y = 9 does not exist in the given set.]

For x = 13, y =10.

So, we have R = {(11, 8), (13, 10)}

Now, R⁻¹ = {(8, 11), (10, 13)}.

Therefore, option A is correct.