Mark the correct alternative in the following:
The range of f(x) = cos [x], for -π/2< x <π/2 is
[x]= -2
f(x)= cos[x]= cos(-2)
= cos2
because cos(-x)= cos(x)
for-1 ≤x<0
[x]=-1
f(x)= cos[x]
=cos(-1)
= cos1
for 0 ≤x< 1
[x]=0
f(x) = cos 0
=1
[x]=1
f(x)=cos 1
Therefore, R(f) = {1, cos 1,cos 2}
Option B is correct.