Mark the correct alternative in the following:
If tan θ + sec θ = ex, then cos θ equals
We know tan2x + 1 = sec2x…(1)
Let tan θ be a and sec θ be b
According to question
a + b =ex
Manipulating and Substituting in 1 we get
⇒ a2 – b2 = -1
⇒ (a-b)( a + b) = -1
⇒ (a-b).ex =-1
⇒ a-b = -e-x
a + b =ex
a-b = -e-x
subtracting above equations we get
2b =ex +e-x