Mark the correct alternative in the following:
If sec x + tan x = k, cos x =
We know tan2x + 1 = sec2x…(1)
Let tan x be a and sec x be b
According to question
a + b =k
Manipulating and Substituting in 1 we get
⇒ a2 – b2 = -1
⇒ (a-b)( a + b) = -1
⇒ (a-b).k =-1
⇒ a-b = -k-1
a + b =k
a-b = -k-1
subtracting above equations we get
2b =k +k-1