Mark the correct alternative in the following:

If , the


tan2x + 1 = sec2x


sin2x+cos2x= 1


∴ cos2x= 1 - sin2x


Substituting in f(x) we get


1 - sin2x+ tan2x + 1






Minimum value of is 0.


∴ f(x)≥ 2.

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