In any ∆ABC, find the value of ∑ a (sin B – sin C)
a(sinB - sinC) + b(sinC - sinA) + c(sinA - sinB)
We know,
By Sine law,
a(Kb-Kc)+b(Kc-Ka)+c(Ka-Kb)
K(ab-ac+bc-ab+ac-bc)=0