Mark the Correct alternative in the following: In any ∆ABC,

Question

Philoid · Accepted Answer

a²(sin B – sin C) + b²(sin C – sin A) + c²(sin A – sin B)

a²sinB – a²sinC + b²sinC – b²sinA + c²sinA – c²sinB

a²sinB – c²sinB + b²sinC – a²sinC + c²sinA – b²sinA

(a² – c²)sin B + (b² – a²)sin C + (c² – b²)sin A

By Sine law,

(a² – c²)bk + (b² – a²)ck + (c² – b²)ak

a²bk – c²bk + b²ck – a²ck + c²ak – b²ak

Considering it as equilateral,

a=b=c

a²bk – c²bk + b²ck – a²ck + c²ak – b²ak=0

Option D