If sec x cos 5x + 1 = 0, where find the value of x.
cos 5x = -cos x
cos 5x+cos x = 0
We know
Here
Now from the above equation it would be,
2cos 3x cos 2x=0
cos 3x cos 2x=0
cos 3x=0 or cos 2x=0
for cos3x=0
for cos2x=0
so the values of the x less than equal to 90° are