Mark the Correct alternative in the following:
In (0, π), the number of solutions of the equation tan x + tan 2x + tan 3x = tan x tan 2x tan 3x is
tan x+tan2x+tan3x -tan xtan2xtan3x=0
tan x + tan2x + tan3x (1-tan xtan2x) = 0
tan x + tan2x = -tan3x (1-tan xtan2x)
tan 3x=-tan3x
2 tan3x=0
tan 3x=0
3x=2nπ
For
n=0, x=0
n=1,
so, there are only two possible solutions
Option D