Mark the Correct alternative in the following:
The number of values of x in the interval [0. 5 π] satisfying the equation 3 sin2 x – 7 sin x + 2 = 0 is
3sin2x-7sin x+2=0
Solving the equation, we get
=19.47122
x= nπ + (-1)n a
For
n=0, x=a
n=1, x = π – a
n=2, x = 2π + a
n=3, x = 3π – a
n=4, x = 4π + a
n=5, x = 5π + a
So, there are 6 values less then 5π.
Option C.