Mark the Correct alternative in the following:

The number of values of x in the interval [0. 5 π] satisfying the equation 3 sin2 x – 7 sin x + 2 = 0 is


3sin2x-7sin x+2=0


Solving the equation, we get




=19.47122


x= nπ + (-1)n a


For


n=0, x=a


n=1, x = π – a


n=2, x = 2π + a


n=3, x = 3π – a


n=4, x = 4π + a


n=5, x = 5π + a


So, there are 6 values less then 5π.


Option C.

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