Mark the Correct alternative in the following:

For all n ∈ N, 3 × 52n + 1 + 23n + 1 is divisible by


Given for all n€ N 3 × 52n+1 + 23n+1


For n=1,


3 × 53 + 24


3 × 125 + 16


375 + 16 = 391


For n=2,


3 × 55 + 27


3 × 3125 +128


9375 + 128 = 9503


H.C.F of 391, 9503 = 17

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