Mark the Correct alternative in the following:

Let P (n): 2n < (1 × 2 × 3 × … × n). Then the smallest positive integer for which P(n) is true is


Given P(n):2n< (1×2×…. ×n)


For n=1, 2<2


For n=2, 4<4


For n=3, 6<6


For n=4, 8<24


the smallest positive integer for which P(n) is true is 4.

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