Mark the Correct alternative in the following:
Let P (n): 2n < (1 × 2 × 3 × … × n). Then the smallest positive integer for which P(n) is true is
Given P(n):2n< (1×2×…. ×n)
For n=1, 2<2
For n=2, 4<4
For n=3, 6<6
For n=4, 8<24
the smallest positive integer for which P(n) is true is 4.