If |z – 5i| = |z + 5i|, then find the locus of z.
z = a + ib
|a+ib-5i| = |a+ib+5i|
|a+ib-5i|2 = |a+ib+5i|2
|a +i(b-5)|2 = |a + i(b+5)|2
a2+(b-5)2 = a2+(b+5)2
a2+b2+25-10b = a2+b2+25+10b
20b = 0
b = 0
b is a imaginary part of z
= y
= 0
Im (z) = 0
So, the locus point is real axis