If n ∈ N, then find the value of in + in + 1 + in + 2 + in + 3.
As we know that,
i = √(-1 ), i2 = -1, i3 = -i, i4 = 1
z = in + in+1 + in+2 + in+3
= in (1+i1+i2+i3 )
= in (1+i-1-i)
= in(0)
= 0