If n N, then find the value of in + in + 1 + in + 2 + in + 3.

As we know that,


i = √(-1 ), i2 = -1, i3 = -i, i4 = 1


z = in + in+1 + in+2 + in+3


= in (1+i1+i2+i3 )


= in (1+i-1-i)


= in(0)


= 0


1