Mark the Correct alternative in the following: If the complex number z = x + iy satisfies the condition |z + 1| = 1, then z lies on

Question

Philoid · Accepted Answer

|z + 1| = 1

|x + iy + 1| = 1

|(1 + x) + iy| = 1

(x + 1)² + y² = 1

(x – (-1))² + (y – 0)² = (1)²

So, we can say that it is a circle with centre (-1,0) and radius 1