Mark the Correct alternative in the following:
The values of k for which is quadratic equation 
has real and equal roots are
given kx2 + 1 = kx + 3x – 11x2
x2(k+11) – x(k + 3) + 1 = 0
as the roots are real and equal then the discriminant is equal to zero.
D = b2 – 4ac = 0
(k+3)2 – 4 (k+11) (1) = 0
K2 + 9 + 6k – 4k – 44 = 0
K2 + 2k – 35 = 0
(k-5) (k+7) = 0
K = 5, -7.
1