Mark the Correct alternative in the following:

If α, β are the roots of the equation , then


given x2-p(x+1)-c=0

x2-px-p-c=0


x2-px-(p+c)=0


as α, β are roots of equation, we get


sum of the roots α + β = p


Product of roots αβ = - (p + c)


Given (1+ α) (1+ β)


= 1 + (α + β) + (α β)


= 1 + p – p – c


= 1 – c.

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