Mark the Correct alternative in the following:
If α, β are the roots of the equation , then
given x2-p(x+1)-c=0
x2-px-p-c=0
x2-px-(p+c)=0
as α, β are roots of equation, we get
sum of the roots α + β = p
Product of roots αβ = - (p + c)
Given (1+ α) (1+ β)
= 1 + (α + β) + (α β)
= 1 + p – p – c
= 1 – c.