Write the solution set of the inequation 
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⇒ 
⇒ 
Case I : x2 – 2x + 1 ≥ 0 and x > 0
(x – 1)2 ≥ 0 and x > 0
So, by taking intersection x > 0
Case II : : x2 – 2x + 1 ≤ 0 and x < 0
(x – 1)2 ≤ 0 and x < 0
Square term is always positive so case II is irrelevant.
Then, the final answer of question is x ∈ (0, ∞)
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