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Mark the Correct alternative in the following:
If , then
Case I : x > 2
1 ≥ 0
It is true that 1 is always greater than 0 so case I is also true x > 2
Case II : x < 2
-1 ≥ 0
It is false that -1 is not greater than 0 so case II is also false.
So, the final solution is x > 2 i.e., x ∈ (2, ∞)