Given: Plane passes through the point A(1, 0, -1).

Plane is perpendicular to the line

To find: Equation of the plane.

Formula Used: Equation of a plane is ax + by + cz = d where (a, b, c) are the direction ratios of the normal to the plane.

Explanation:

Let the equation of the plane be

ax + by + cz = d … (1)

Substituting point A,

a – z = d

Since the given line is perpendicular to the plane, it is the normal.

Direction ratios of line is 2, 4, -3

Therefore, 2 + 3 = d

d = 5

So the direction ratios of perpendicular to plane is 2, 4, -3 and d = 5

Substituting in (1),

2x + 4y – 3z = 5

Therefore, equation of plane is 2x + 4y – 3z = 5